Omicron Alert: For a randomly chosen person in Scotland the chance of becoming infected with some sort of Covid on any particular day is currently (10th December 2021) about 1 in 1000 and rising. Please try to assess your own risk. The following procedure may help:
A SIMPLE SELF DIAGNOSTIC TOOL
CONSIDER THE IDEALIZED ASSUMPTIONS THAT ON ANY PARTICULAR DAY , YOU
WILL, WITH PROBABILITY P=1/2000, BE INFECTED WITH COVID, WHERE INFECTIONS
ON DIFFERENT DAYS ARE TAKEN TO OCCUR INDEPENDENTLY.
LET N=NUMBER OF DAYS UNTIL YOUR FIRST INFECTION
THEN N POSSESSES A PROBABILITY DISTRIBUTION WHICH IS
GEOMETRIC WITH PROBABLITY P=1/2000
IN PARTICULAR, THE MEAN OR EXPECTATION OF N IS
E(N)= 2000
AND THE STANDARD DEVIATION OF N IS, TO A CLOSE APPROXIMATION
ST.DEV. (N)= 2000
IF, FOR EXAMPLE, YOU ARE WORKING IN RETAIL AND YOUR CUSTOMERS ARE NOT
COMPELLED TO WHERE MASKS, THEN THE DAILY PROBABILITY OF INFECTION P
COULD BE MUCH HIGHER THAN IF YOU ARE WORKING FROM HOME
IF FOR EXAMPLE, P=1/100, THEN YOUR EXPECTED NUMBER OF DAYS TO FIRST
INFECTION IS E(N)=100 WITH APPROXIMATE STANDARD DEV IATION 100.
IF YOU HAVE BEEN DOUBLY VACCINATED THEN YOU COULD CONSIDER DIVIDING
YOUR SUBJECTIVE ASSESSMENT OF P BY 9. IF P=1/900. THEN E(N)=900 WITH
APPROXIMATE STANDARD DEVIATION 900.
THIS PROVIDES A SIMPLE WAY OF THINKING ABOUT YOUR CHANCES OF INFECTION.
A BASELINE POPULATION VALUE OF P IS
P*= NUMBER OF DAILY INFECTIONS / POPULATION SIZE
FOR EXAMPLE.,IF THE NUMERATOR AND DENOMINATOR ARE RESPECTIVELY
3000 AND 6000000, THEN P*=1/2000
WHEN SUBJECTIVELY ASSESSING YOUR OWN P YOU COULD C ONSIDER HOW
MUCH AT RISK YOU ARE RELATIVE TO A RANDOMLY SELECTED MEMBER OF THE
POPULATION WITH P=P*.
PROBABILITIES FOR GEOMETRIC DISTIBUTION
NOTE THAT
F(n) = Prob (N>n) can be calculated as the nth power of 1-P, for your subjective choice of P
You can therefore easily calculate your probability of not being infected with COVID during the next n days, for any specified value of n
(Approximate) Quartiles: The first or lower (approximate) quartile Q1 of N is the value of n such that F(n)=3/4.
Therefore
Q1= log (3/4) / log (1-P).
where log denotes the natural logarithm
Similarly, the second (approximate) quartile, or median of N is
Q2= log (1/2)/log (1-P)
and the third or upper (approximate) quartile of N is
Q3= log (1/4)/log (1-P)
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